Python: Triangle, Pentagonal, and Hexagonal
Python: Triangle, Pentagonal, and Hexagonal
Problem No.45 @ Projecteuler
Completed on: Thu, 11 Jul 2019, 21:31
Another straight-forward problem, in this task I create three functions each for Triangle, Pentagonal, and Hexagonal and we return the value of the formulas as been stated in the problem.
Using a for loop and a number range, I store the results in a list tn, pn, hn. then comparing the values in the three lists searching for same value.
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The Code:
# P45
# Solved
# Completed on Thu, 11 Jul 2019, 21:31
def tn (n) :
return int(n*(n+1)/2)
def pn(n):
return int(n*(3*n-1)/2)
def hn (n):
return int(n*(2*n-1))
tn_list =[]
pn_list=[]
hn_list=[]
n = 0
# Notes: I run the code for large range, but to save more time after 5000 i select +10,000 each time.
for n in range (5000,60000):
tn_list.append(tn(n))
pn_list.append(pn(n))
hn_list.append(hn(n))
print ([x for x in tn_list if x in pn_list and x in hn_list])
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