Python: Powerful Digit Counts
Python: Powerful Digit Counts
Problem No.63 @ ProjectEuler
Completed on: Completed on Thu, 11 Jul 2019, 17:21
Just to make my post simple, i am quoting from ProjectEuler page
The 5-digit number, 16807=75, is also a fifth power. Similarly, the 9-digit number, 134217728=89, is a ninth power.
How many n-digit positive integers exist which are also an nth power?
Then, we need to find the loop that will solve this, and we did..
|
|
The Code:
# P63
# Power digit count
# Solved
# Completed on Thu, 11 Jul 2019, 17:21
c = 0
for x in range (1,50):
for p in range (1,50) :
if (len(str(x**p)) == p ):
c += 1
print(‘\n We have {} n-digit integers exist which are also an nth power.’.format(c))
Follow me on Twitter..
Taking pictures is not my main daily practices, but when i start playing with my camera, i really enjoy my self.
Thanks for visiting my Space..
Ali's Photography Space... 