Python: Largest product in series
Python: Largest product in a series
Problem 8 @ projectEuler
In Problem 8, ProjectEuler wants to find the thirteen adjacent digits in the 1000-digit number that have the greatest product.
In this task i use a for loop to check each 13-dig set, each time creating a set of 13 digits starting from (0,13) then (1,14)..(2,15)….. and so-on. for each set i get the product of its digits and store it in an a array of [set,total] each time if total of the new set is larger than what we have in the array[total] then we write the new values to the array, we call the array largest.
The Code:
# Largest product in a series
# ProjectEuler: Problem 8
num=’7316717653133062491922511967442657474235534919493496983520312774506326239578318016984801869478851843858615607891129494954595017379583319528532088055111254069874715852386305071569329096329522744304355766896648950445244523161731856403098711121722383113622298934233803081353362766142828064444866452387493035890729629049156044077239071381051585930796086670172427121883998797908792274921901699720888093776657273330010533678812202354218097512545405947522435258490771167055601360483958644670632441572215539753697817977846174064955149290862569321978468622482839722413756570560574902614079729686524145351004748216637048440319989000889524345065854122758866688116427171479924442928230863465674813919123162824586178664583591245665294765456828489128831426076900422421902267105562632111110937054421750694165896040807198403850962455444362981230987879927244284909188845801561660979191338754992005240636899125607176060588611646710940507754100225698315520005593572972571636269561882670428252483600823257530420752963450
‘
v1=0
v2=13
set1=num[v1:v2]
largest =[0,0]
tot=1
for x in range((1000)):
set1=num[v1:v2]
for each in set1:
tot=tot * int(each)
if tot > largest [1]:
largest[0] = set1
largest[1] = tot
tot=1
tot =1
v1=v1+1
v2=v2+1
print’The thirteen adjacent digits are’,largest[1],’there product is ‘,largest[0]
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