## Python Project

**Python: Prime Numbera **

** Is it Prime**

In a simple way, a **Prime** number is a number that cannot be made by multiplying other numbers. So 4 is **Not Prime **because we can say that 4 = 2 x 2, 6 is **Not Prime** because it can be produced by multiplying 3 x 2; but 5 **Is Prime** because we can’t find any integer numbers that can produce 5.

Numbers such as 1, 3, 5, 7, 11, 13 … all are Prime Numbers.

**T**his function will ask the user to write a number then we will examine it to see whether it is a prime or not.

**The Code:**

num=int(input(“Enter a number: “))

def is_prime(num):

result=”Prime”

for t in range (2,num):

if num%t==0 :

result=”Not Prime”

break

return result

print num,’is’,is_prime(num)

## Python Project

**Python: Fibonacci Numbers**

**Even Fibonacci Numbers**

__Fibonacci Sequence__ is generated by adding the previous two terms, so the N number in the sequence will be Xn=(Xn-1) + (Xn-2). Example: by starting with 1 and 2, the first 10 terms will be: 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, …

**The Task:** Get the Fibonacci sequence range from the user and count how many even valued terms is there. The user range should not be more than 10000 number.

**The Code:**

def get_Fibonacci_Sequence(rfrom,rto):

n1=rfrom

n2=rfrom+1

count=0

for x in range (rfrom,rto):

fab=n1+n2

n1=n2

n2=fab

# Check if the fab is even, the increment the counter

if fab%2==0 :

count =count +1

# After finish print the output

print”Between”,rfrom,” and “,rto,” there is “,count,”even Fibonacci number.”

range_ok =”no”

while range_ok==”no”:

print(‘Your range must be less than 10,000:’)

# Get the numbers from the user.

rfrom=int(input(‘Enter the range From:’))

rto=int(input(‘Enter the range To:’))

# Check if the numbers are less than 10000

if (rto – rfrom) < 10000 : range_ok ="yes"

#Call the function

get_Fibonacci_Sequence(int(rfrom),int(rto))

## Python Project

**Python: Pluralise a Word**

**Loop through a dictionary and pluralise a word**

One of Python Exercises on @PyBites codechalleng is to loop through a given dictionary of people and the number of games they’ve won then print out the users name and how many games they’ve won in the following format: “sara has won n games” and pluralise the word game to suit the number of games won.

we assume the dictionary is

games_won = dict={‘sara’:0, ‘bob’:1, ‘tim’:5, ‘julian’:3, ‘jim’:1}

**The Code:**

games_won ={‘sara’:0, ‘bob’:1, ‘tim’:5, ‘julian’:3, ‘jim’:1}

def print_game_stats(games_won):

for key,val in games_won.items():

print(“{} has won {}{p}”.format(key, val,p=” game” if val ==1 else ” games” ))

print_game_stats(games_won)

## Python Project

**Python: Sum n numbers**

**Bites of Python exercises**

I found this Python Exercises on the at **PyBites codechalleng** and i love the idea of solving problems and this will let me learn more, so thanks guys **@pybites**.

So this time the challenge is to Write a function that can sum up N numbers. The function should receive a list of N numbers, If no argument is provided, return sum of numbers 1..100.

I hope i did this right, here is my function; the result seems to be fine i am still learning so … sorry if i misunderstood.

def sum_up(my_nums=range(1,100)):

total=0

print”The List of number/s “,my_nums

for x in range (len(my_nums)):

total=total+int(my_nums[x])

print”Total is:”,total

print(“This function will sum up a given list of numbers.\nWhen you finish typping the numbers just press “”Enter””\nIf you did not enter any numbers i will assume the list is [1,100]”)

#Get the list from the user

n=input(“Type the numbers:”)

#In case the user enter some spaces in his number, we should remove it

the_n=n.replace(” “, “”)

#Here we are calling the functin

sum_up() if the_n ==”” else sum_up(the_n)

## Python project

**Python: Draw Flower**

**Drawing with Python**

In this post i tried to draw another flower using arcs of circles, i get a simple one and i guess with more sizes we can do more complex shape.

You can play with the code and change the numbers, size and rotation degree and let’s see what we will have.

t = turtle.Turtle()

t.hideturtle()

t.pendown()

for x in range (30):

t.circle(60,70)

if x %3==0:

t.circle (10,90)

## Python Project

**Python: Binary Search**

**Binary Search**

**Definition**:

**Binary Search** is a search algorithm that finds the __position __of a target value within a __sorted__ array. Binary search compares the target value to the middle element of the array.

**In** this code we are writing a Python code to find the target in a sorted given array and get its position without using any python math packages.

**The case:** We have an Array (arr=[2,3,5,6,8,10,11,13,15,16,19]) our target is 13, so we want the position of 13.

We are setting the first position as (pos_s=0) and the end position as (pos_e= the length of the array -1) and we will use recursive function.

Recursive Function: is a computer function or procedure that calling it self

**The Code:**

arr=[2,3,5,6,8,10,11,13,15,16,19]

target=11

pos_s =0

pos_e=int(len(arr)-1)

midarr =0

def bsearch(arr,target,pos_s,pos_e):

midarr=(pos_s+pos_e)/2

if arr[midarr] < target:

pos_s = midarr +1

bsearch(arr,target,pos_s,pos_e)

elif arr[midarr] > target:

pos_e = midarr -1

bsearch(arr,target,pos_s,pos_e)

elif arr[midarr] == target:

print(‘The target was: ‘,target, ‘ The key of our target is: ‘,midarr)

return

print(arr)

# Call the functin

bsearch(arr,target,pos_s,pos_e)

## Python Project

**Python: Armstrong Numbers**

**Check for Armstrong number in a range**

**In** our last post (‘**Check if a Number is Armstrong**‘) we wrote a codes to check a given number and see whether it is an Armstrong or Not.

**Today**, we want to go through a set of numbers and see how many Armstrong numbers are there.

Before calling the

‘armstrong_in_range()’and just to keep the code as less as we can, I assume the two numbers has the same number of digits, also I am getting the power (p) and the range numbers (n1, n2) out-side of this function and passing all as variables.

def armstrong_in_range(p,n1,n2):

my_sum = 0

count = 0

for num in range (n1,n2):

tot=num

for arm in range(p):

my_sum = my_sum + ((num % 10)**p)

num = num // 10

if my_sum == tot:

print(‘\nThe number {} is Armstrong.’.format(tot))

my_sum=0

count = count +1

else:

my_sum=0

print(‘\nWe have {} armstrong number(s)’.format(count))